I want to switch over to a closed transfer
#21
Posted 20 May 2009 - 02:25 PM
#22
Posted 20 May 2009 - 04:51 PM
#23
Posted 20 May 2009 - 05:04 PM
#24
Posted 20 May 2009 - 05:21 PM
Are you telling me that all that stuff I learned in college is actually useful?I approve in this instance.According to Ideal Gas Law:PV = nRTP = 3 psig = 17.69 psia = 121968 Pa V ≈ 7 gal = .0265 m3R = 8.314 m3-Pa/mol-KT = 68F = 20C = 293Kn = (121968*.0265)/(8.314*293) = 1.33 mol * 44 g/mol = 58.3 g = 0.128 lbmat 3 psig 0.128lbs of CO2 will be in the carboy. Some of it was there to begin with, but most was added. Divide it by 5 and you find that one transfer will use about 2.5% of a 5 lb cylinder.
#25
Posted 20 May 2009 - 05:26 PM
Funny this is almost the same as what I calculated (I got 0.15 lb using 70 degrees and atmospheric pressure). However, I started doubting myself because I then used what I calculated to work backwards and see how many corny kegs you could carbonate and dispense and the numbers seemed wrong. (I used 2.5 volumes of CO2 for carbonation + 1 volume for dispensing). I was getting that a 5 lb tank would carb and dispense 25 corny kegs and even under ideal conditions that seems way too high. However I now think I realize one of my errors, I was not taking into account the pressure in the keg when carbonating, I was still using atmospheric pressure. So I didn't post my calculations since I wasn't sure.I will say that one time I weighed my tank before and after pressure racking 10 gallons. Unfortunately I didn't write down the amount of CO2 used. But I do remember being surprised how little it was. I'm fairly certain that it was in the range we calculated, and certainly not more than 0.25 lb.According to Ideal Gas Law:PV = nRTP = 3 psig = 17.69 psia = 121968 Pa V ≈ 7 gal = .0265 m3R = 8.314 m3-Pa/mol-KT = 68F = 20C = 293Kn = (121968*.0265)/(8.314*293) = 1.33 mol * 44 g/mol = 58.3 g = 0.128 lbmat 3 psig 0.128lbs of CO2 will be in the carboy. Some of it was there to begin with, but most was added. Divide it by 5 and you find that one transfer will use about 2.5% of a 5 lb cylinder.
#26
Posted 20 May 2009 - 05:30 PM
I've often thought that if college coursework was directly tied to brewing, people would pay a lot more attention. Thermodynamics would have been much more interesting. Fluid mechanics would have been much more fun. Statics, strengths of materials, structural analysis, steel design...I would have learned so much more if beer was involved. I still would have hated dynamics though.Are you telling me that all that stuff I learned in college is actually useful?I approve in this instance.
#27
Posted 20 May 2009 - 05:38 PM
Another ME, or are you a CE?I've often thought that if college coursework was directly tied to brewing, people would pay a lot more attention. Thermodynamics would have been much more interesting. Fluid mechanics would have been much more fun. Statics, strengths of materials, structural analysis, steel design...I would have learned so much more if beer was involved. I still would have hated dynamics though.
#28
Posted 20 May 2009 - 06:01 PM
I didn't know you were an accountant.I've often thought that if college coursework was directly tied to brewing, people would pay a lot more attention. Thermodynamics would have been much more interesting. Fluid mechanics would have been much more fun. Statics, strengths of materials, structural analysis, steel design...I would have learned so much more if beer was involved. I still would have hated dynamics though.
#29
Posted 20 May 2009 - 06:12 PM
Crazy stuff, eh?Are you telling me that all that stuff I learned in college is actually useful?I approve in this instance.
One problem is that the beer already has CO2 in it, maybe like 1.5 volumes. So that would throw off your calc. I'd have to work the numbers, but 25 doesn't sound too crazy for a 5 pound tank. Look at it this way, 5 lbs of CO2 is 51.5 moles. At atmospheric pressure, that's 1,239 liters, or 327 gallons, of gaseous CO2. One "volume" of CO2 for a 5 gallon keg is 5 gallons of atmospheric pressure CO2, so there are 65.4 volumes of CO2 in a 5lb tank (with respect to a 5 gallon keg). Divide that by 25 kegs and you get 2.62 volumes per keg. Then add the 1.5 volumes that is dissolved into the beer during the fermentation process and you get 4.12 volumes of CO2 'used' per keg. That sounds reasonable to me.Funny this is almost the same as what I calculated (I got 0.15 lb using 70 degrees and atmospheric pressure). However, I started doubting myself because I then used what I calculated to work backwards and see how many corny kegs you could carbonate and dispense and the numbers seemed wrong. (I used 2.5 volumes of CO2 for carbonation + 1 volume for dispensing). I was getting that a 5 lb tank would carb and dispense 25 corny kegs and even under ideal conditions that seems way too high. However I now think I realize one of my errors, I was not taking into account the pressure in the keg when carbonating, I was still using atmospheric pressure. So I didn't post my calculations since I wasn't sure.I will say that one time I weighed my tank before and after pressure racking 10 gallons. Unfortunately I didn't write down the amount of CO2 used. But I do remember being surprised how little it was. I'm fairly certain that it was in the range we calculated, and certainly not more than 0.25 lb.
#30
Posted 20 May 2009 - 07:12 PM
CE.Another ME, or are you a CE?
Cool, makes more sense. Thanks for posting that.One problem is that the beer already has CO2 in it, maybe like 1.5 volumes. So that would throw off your calc. I'd have to work the numbers, but 25 doesn't sound too crazy for a 5 pound tank. Look at it this way, 5 lbs of CO2 is 51.5 moles. At atmospheric pressure, that's 1,239 liters, or 327 gallons, of gaseous CO2. One "volume" of CO2 for a 5 gallon keg is 5 gallons of atmospheric pressure CO2, so there are 65.4 volumes of CO2 in a 5lb tank (with respect to a 5 gallon keg). Divide that by 25 kegs and you get 2.62 volumes per keg. Then add the 1.5 volumes that is dissolved into the beer during the fermentation process and you get 4.12 volumes of CO2 'used' per keg. That sounds reasonable to me.
#31
Posted 20 May 2009 - 07:21 PM
#32
Posted 20 May 2009 - 09:56 PM
Hey JK, I thought you were a professional football player. Maybe you are. All the quantum mechanics, thermodynamics and statistical mechanics I learned in college stayed back on campus. All those labs and I have never used any of it! But it's nice to see some physics applied to brewing.Of course, that's theoretical. It doesn't take into account all the leaks in your system.
#33
Posted 21 May 2009 - 07:19 AM
I'm well rounded.Hey JK, I thought you were a professional football player. Maybe you are. All the quantum mechanics, thermodynamics and statistical mechanics I learned in college stayed back on campus. All those labs and I have never used any of it! But it's nice to see some physics applied to brewing.
#34
Posted 21 May 2009 - 08:16 PM
#35
Posted 22 May 2009 - 03:12 AM
#36
Posted 23 May 2009 - 06:31 AM
#37
Posted 23 May 2009 - 06:33 AM
The problem I see with this is that it really wouldn't be a closed transfer. If you pull liquid out with a pump, you need to let air in to replace the liquid.Anyone do closed transfers by pulling the beer out with a pump?
#38
Posted 24 May 2009 - 06:05 AM
#39
Posted 26 May 2009 - 08:49 AM
#40
Posted 26 May 2009 - 09:02 AM
Try a different cap? I do 2ndary-to-keg transfers all the time and have never had a problem with the cap blowing off unless I forgot to pull the pressure release on the keg.Back to the drawing board. My primary-2ndary transfer was smooth, the carboy cap fit the primary snug. However while waiting for a mash on saturday I decided to xfer to keg 2 kolschs from glass 5 gallon carboys. The purple carboy cap does not fit these, and the orange does, but not real snug. Any pressure to push was just popping the cap off the carboy, making it a huge PITA. So I will probably need to work on a 2 hole rubber stopper setup, or a ring clamp of some sort. Any other ideas?
0 user(s) are reading this topic
0 members, 0 guests, 0 anonymous users